How do you do the trapezoidal rule to compute $\int log x d x$ $int logxdx$ from [1,2]?

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How do you do the trapezoidal rule to compute $\int log x d x$ $int logxdx$ from [1,2]?

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Answer 1 · 2015-06-19T23:04:40

$\int_{1}^{2} log x d x \approx \frac{log 2}{2} \approx 0.34657$ $int_1^2logx dx≈log2/2≈0.34657$

Explanation:

Using the trapezoidal rule, the expression $\int_{1}^{2} log x d x$ $int_1^2logx dx$ becomes $(2 - 1) [\frac{log 1 + log 2}{2}] = \frac{log 2}{2} \approx 0.34657$ $(2-1)[(log1+log2)/2]=log2/2≈0.34657$ .

It's important to notice that it's only an approximate value (n=1) and it contain a percentage of error : the correct value would be around 0.38629, but with this formula we found approximately 0.34657.

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How do you do the trapezoidal rule to compute $\int log x d x$ $int logxdx$ from [1,2]?

1 Answer

Explanation:

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How do you do the trapezoidal rule to compute ∫logxdxint logxdx from [1,2]?

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Explanation:

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How do you do the trapezoidal rule to compute $\int log x d x$ $int logxdx$ from [1,2]?