Question #c552a

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Question #c552a

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Answer 1 · 2015-06-15T10:14:27

A 13-g bullet that possesses 1.6 kg-m/s of momentum moves with 123.077 m/s.

Explanation:

We all know that,
Momentum(P)=Mass(M) . velocity(V)
$V = \frac{P}{M}$ $V=P/M$
$V = \frac{1.6 \times 1000 g r a m \times \frac{m e t e r}{sec}}{13 g r a m}$ $V=(1.6xx1000 gramxx(meter)/sec)/(13gram)$
$V=(1.6xx1000 cancel(gram)xx(meter)/sec)/(13cancel(gram)$
$V=123.07m/s$

A 13-g bullet that possesses 1.6 kg-m/s of momentum moves with 123.077 m/s.

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Question #c552a

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