Question #c552a

1 Answer
Arunraju Naspuri
Jun 15, 2015

A 13-g bullet that possesses 1.6 kg-m/s of momentum moves with 123.077 m/s.

Explanation:

We all know that,
Momentum(P)=Mass(M) . velocity(V)
V=P/M
V=(1.6xx1000 gramxx(meter)/sec)/(13gram)
V=(1.6xx1000 cancel(gram)xx(meter)/sec)/(13cancel(gram)
V=123.07m/s

A 13-g bullet that possesses 1.6 kg-m/s of momentum moves with 123.077 m/s.

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