How do you solve the inverse trig function $cos (arccos 3 π)$ $cos (arccos 3pi)$ ?

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How do you solve the inverse trig function $cos (arccos 3 π)$ $cos (arccos 3pi)$ ?

1 Answer

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Answer 1 · 2015-06-11T15:55:37

It does not exist.

Explanation:

$y = arccos (x)$ $y=arccos(x)$ is a function defined in the interval $[- 1, 1]$ $[-1,1]$ So it does not exist for the value $3 π > 1$ $3pi>1$ .
$arccos (3 π)$ $arccos(3pi)$ does not make any sense!

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How do you solve the inverse trig function $cos (arccos 3 π)$ $cos (arccos 3pi)$ ?

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How do you solve the inverse trig function cos(arccos3π)cos (arccos 3pi)?

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Explanation:

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How do you solve the inverse trig function $cos (arccos 3 π)$ $cos (arccos 3pi)$ ?