How do you factor x33x+2?

2 Answers
May 31, 2015

First notice that substituting x=1 results in x33x+2=0

So (x1) is a factor.

Use synthetic division to find the remaining factor...

x33x+2=(x1)(x2+x2)

Notice that x=1 is also a root of x2+x2

So we have another (x1) factor...

x2+x2=(x1)(x+2)

So the complete factorization is:

x33x+2=(x1)(x1)(x+2)

May 31, 2015

f(x)=x33x+2=0

Since (a+b+c+d=0), then one factor is (x1)

Factored form: f(x)=(x1)(x2+x2)=(x1)(x1)(x+2)=

=(x1)2(x+2)