How do you solve 2^x = 10?

1 Answer
May 30, 2015

For this kind of question you should use logarithm.
For example;
a^b = c => log_a(c) =b
Therefore for our question;
2^x=10 => log_2(10)=x => x= log_2(2*5) => x= log_2(2) +log_2(5)
=> x=1+log_2(5)
x= 1+2.32 =ul3.32