How do you factor #x^2 + 13x + 36 #?

2 Answers
Susanns · Christopher P.
May 24, 2015

#(x+4)(x+9)=0#

Your answer would be x=-4 and x=-9.

Explanation::

#(x+4)(x+9) #
#x " times " x = x^2#
#x(9)+x(4)= 13x#
#4 " times " 9= 36#
= #x^2+13x+36#

Nghi N.
May 24, 2015

#x^2 + 13x + 36 =# (x - p)(x - q).
Find p, and q, knowing sum = b = 13 and product c = 36. Compose factor pairs of 36-> (2, 18)(2, 12)(4, 9). this last sum is 9 = b. Then p = 4 and q = 9

y = (x + 4)(x + 9)

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