How do you simplify #(2a^[2] b^[-3])^3/ (9a^[-3] b^[2]) ^-1/2#?
1 Answer
May 19, 2015
Let's just bear in mind three important laws of exponents:
-
#a^n/a^m=a^n-m# -
#(a^n)^m=a^n*m# -
#a^-n=1/a^n#
Now, let's proceed:
