How do you find the domain of $p(x)=x^2-2x+8$ ?

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Answer 1 · 2015-05-11T19:52:50

The domain of a function is basically all the values that $x$ can take.

In a polynomial function like yours, $x$ can be any real numbers, so the domain is :
$D = RR$ .

If your function was something like $p(x) = 1/x$ , you would make sure that zero is excluded since you can't divide by zero :

$D = RR-{0}$ or $D = ]-oo,0[ uu ]0, +oo[$ .

How do you find the domain of p(x)=x^2-2x+8p(x)=x^2-2x+8?