How do you simplify $(x + 3) (x - 2)$ $(x+3) (x - 2)$ ?

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Answer 1 · 2015-05-11T18:59:51

$= x^{2} + x - 6$ $= x^2+x-6$

The two brackets are multiplied by each other.

To start, multiply the first term in the first bracket by the first term in the second bracket.
$= (x) (x) = x^{2}$ $=(x)(x) = x^2$
In other words, x squared or x to the power of two.
For right now, your equation is:
$x^{2}$ $x^2$
Multiplying the first term in the first bracket ( $x$ $x$ ) by the second term in the second bracket = $(- 2)$ $(-2)$
Your equation will now become:
$x^{2} - 2 x$ $x^2-2x$
multiplying the second variable in the first bracket by the first variable in the second bracket.
This is going to be $(3) (x)$ $(3)(x)$
Your equation will now become:
$x^{2} - 2 x + 3 x$ $x^2-2x+3x$
You now have to multiply the second term in the first bracket by the second term in the second bracket.
This is going to be $(3) . (- 2)$ $(3).(-2)$

Your equation will now look like
$x^{2} - 2 x + 3 x - 6$ $x^2-2x+3x-6$

$- 2 x + 3 x = x$ $-2x+3x= x$

You now have your simplified answer $x^{2} + x - 6$ $color(red)(x^2+x-6$

How do you simplify (x+3) (x - 2)(x+3)(x−2) (x+3) (x - 2)?