Question #ae278

1 Answer
Bharat K.
Apr 28, 2015

Eff = W/Q_(hot)
where Q_(hot) is the heat absorbed from hot reservoir and,
W = 1250 J (Work done by heat engine)

therefore, Q_(hot) = 1250/0.24 = 5208.33 J (Answer A)

Now, W = Q_(hot) - Q_(cold)
where Q_(cold) is the heat transferred to cold reservoir.

Implies,
Q_(cold) = Q_(hot) - W = 5208.33 - 1250 = 3958.33 J (Answer B)

Related questions
Impact of this question
998 views around the world
You can reuse this answer
Creative Commons License