Question #ae278

1 Answer
Bharat K.
Apr 28, 2015

#Eff = W/Q_(hot)#
where #Q_(hot)# is the heat absorbed from hot reservoir and,
W = 1250 J (Work done by heat engine)

therefore, #Q_(hot) = 1250/0.24 = 5208.33# J (Answer A)

Now, #W = Q_(hot) - Q_(cold)#
where #Q_(cold)# is the heat transferred to cold reservoir.

Implies,
#Q_(cold) = Q_(hot) - W = 5208.33 - 1250 = 3958.33# J (Answer B)

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