Question #384cf

1 Answer
David Y.
Apr 9, 2015

About 0.13 nmol/day

Unless I'm missing something, the rate enhancement is simply the factor by which the rate increases. In this case #10^9# times when the enzyme is added.

So the rate without the enzyme would be #(1500 nmols^-1)/10^9#

This is equal to #1.5*10^(-6)" nmols"^(-1)#

To convert to the desired unit

#(1.5*10^(-6) nmol)/s*(3600 s)/(hr) * (24 hr)/(day) = 0.13" nmol/day"#

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