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How would you multiply #(x+8)(x - 8)#?

1 Answer

Apr 6, 2015

#x^2-64#
This is a difference of squares where:
#(a^2-b^2) = (a+b)(a-b)#

If we let #a=x# and #b=8#
#(x^2-8^2) = (x+8)(x-8)#

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