How do you graph the system of inequalities #y≥ -5# and #x≥6#?

1 Answer
Joe D.
Apr 2, 2015

Lets start by graphing #y>=-5#

First graph #y = -5# line. The inequality includes #-5# so our line will be a solid line, not a dashed line.

Then take a random point (#y#-axis #!= -5#), lets say #(0,0)#. This point satisfies the inequality so we will shade our line's side which includes #(0,0)#.
The resulting graph should look like this:

graph{y >= -5 [-10, 10, -20, 20]}

Now lets graph #x>=6#

In order to graph this inequality we need to graph the #x=6# line.
Since the inequality includes #6#, our line will be a solid line.

Lets take a random point to determine which part will be shaded.

#(7,0)#
#7>=6# satisfied.

So the part of the coordinate plane where #(7,0)# lies will be shaded.
The graph will look like this:

graph{x>=6 [-10, 10, -20, 20]}

Now, there is an area which is shaded by both graphs. That area is the result of this problem. Because it means both inequalities are satisfied in that area.

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