Question #1068b

1 Answer
MeneerNask
Mar 21, 2015

You have to distinguish between heat capacity C and specific heat c, which is heat capacity per gram, so #C=c*m#

We now set up an equation, because heat gained by the water equals heat lost by the pellet. From both we know start and end temperature, and thus the change #DeltaT#
The specific heat of water #c_w# can be found to be #4.18J//g*^oC#

So here goes (water left, pellet right):

#c_w*m*DeltaT_w=C_p*DeltaT_p#

Fill in what we know:

#4.18*m*(54.8-22.7)=52*(121-54.8)->#

#124.2*m=3442.4->m=27.7g#

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