What mass (in g) of NaCl is needed to prepare 1.5 L of a 3.0 M salt water solution?
2 Answers
Mar 20, 2015
263.2g are required.
The number of moles of NaCl in 1.5L of a 3.0M solution
Using:
So 1 mole NaCl weighs 58.5g
So the weight of 4.5 moles = 4.5 x 58.5 = 263.25g
Mar 20, 2015
The formula that you will use is:
Grams = Molarity X liters X formula mass of solute
So for your problem:
grams = 3 X 1.5 X 58