If you have 12 mol FeCl3 and 12 mol O2, which would be the limiting reactant? (The equation is 4 FeCl3 + 3 O2 → 2 Fe2O3 + 6 Cl2)

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If you have 12 mol FeCl3 and 12 mol O2, which would be the limiting reactant? (The equation is 4 FeCl3 + 3 O2 → 2 Fe2O3 + 6 Cl2)

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Answer 1 · 2015-03-20T12:45:58

The limiting reactant would be your $FeCl_3$ .

This is because you need 4 of mol $FeCl_3$ to produce 2 mol of $Fe_2O_3$ while only 3 mol of $O_2$ as the reaction proceed. So, you will exhaust first your $FeCl_3$ supply, therefore making it your limiting reactant.

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If you have 12 mol FeCl3 and 12 mol O2, which would be the limiting reactant? (The equation is 4 FeCl3 + 3 O2 → 2 Fe2O3 + 6 Cl2)

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