Question #4f42d

1 Answer
Gió
Mar 11, 2015

The condition for your line to be perpendicular to the given one is that:
#m_1*m_2=-1#
where #m# is the gradient (or slope) of the line.
Your line CA has slope = #m_1=(Deltay)/(Deltax)=(2-(-3))/(-8-7)=-1/3#
So your perpendicular line will have slope #m_2=3#.

Now, given the coordinates of a point such as (#x_3,y_3#), you can determine the equation of a specific line perpendicular to CA as:
#y-y_3=m_2(x-x_3)#

hope it helps

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