How to calculate pKa of $H C l$ $HCl$ ?

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How to calculate pKa of $H C l$ $HCl$ ?

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Answer 1 · 2014-11-28T19:45:44

The ionisation of HCl can be shown as:

$H C l + H_{2} O \to H_{3} O^{+} + C l^{-}$ $HCl + H_2O -> H_3O^+ + Cl^-$

$K_{a}$ $K_a$ can be calculated as the ratio of the product of the concentrations of the products to that of the reactant, that is,

$K_{a} = \frac{[H_{3} O^{+}] [C l^{-}]}{[H C l]}$ $K_a= ([H_3O^+][Cl^-])/([HCl])$

Since $H C l$ $HCl$ is a strong acid, the value of $K_{a}$ $K_a$ turns out to be very large, that is,

$K_{a} = \frac{10^{7}}{1} = 10^{7}$ $K_a=10^7/1=10^7$ (approx.)

The value of $p K_{a}$ $pK_a$ is given by

$p K_{a} = - {log K}_{a}$ $pK_a=-logK_a$
$p K_{a} = - ({log 10}^{7})$ $pK_a=-(log10^7)$
$p K_{a} = - (7) = - 7$ $pK_a=-(7)=-7$

You can learn more about finding the values of $K_{a}$ $K_a$ and $p K_{a}$ $pK_a$ [here.](https://www.khanacademy.org/science/organic-chemistry/organic-structures/acid-base-review/v/ka-and-pka-derivation)

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