Question #3973b

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Answer 1 · 2014-11-10T05:19:53

The molar mass for the gas in the example problem is #42 g/(mol)#.

Starting with the definition of molar mass,

#molar mass = (grams)/(mol)#

and solve for the number of moles to get the equation

#mol = (grams)/(molar mass)#.

This equation can be substituted into the ideal gas law, #PV = nRT#, to get

#PV=(gRT)/(molar mass)#

and rearranging this to solve for molar mass gives

#molar mass=(gRT)/(PV)#

with this and some simple unit conversions, we can now calculate.

#molar mass = (1.62g xx 0.0821 xx 293K)/(0.9842 atm xx 0.941 L) = 42 g/(mol)#

Hope this helps.