How do you evaluate $x^{2} + 2 x - 1$ $x^2+2x-1$ when $x = 2$ $x=2$ ?

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Answer 1 · 2014-10-27T19:03:27

All you need to do is replace $x$ $x$ with $2$ $2$ since it has been given $x = 2$ $x=2$ .

So,
$x^{2} - 2 x - 1 = {(2)}^{2} + 2 (2) - 1 = 4 + 4 - 1 = 7$ $x^2-2x-1 = (2)^2+2(2)-1 = 4+4-1 = 7$

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