Question #753ae

1 Answer
Gaurav
Oct 22, 2014

#F(θ)=(sec(theta)tan(theta))/(1+sec(θ))^2#

Explanation :

#F(θ)=sec(θ)/(1+sec(θ))#

let's #y=f(x)/g(x)#

Using Quotient Rule,

#y'=(f'(x)g(x)-f(x)g'(x))/(g(x))^2#

Similarly following for the given problem and differentiating with respect #theta#,

#F(θ)=sec(θ)/(1+sec(θ))#

#F(θ)=((1+sec(θ))(sec(theta)tan(theta))-sec(theta)(sec(theta)tan(theta)))/(1+sec(θ))^2#

#F(θ)=(sec(theta)tan(theta))/(1+sec(θ))^2#

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