# What is the force, in terms of Coulomb's constant, between two electrical charges of -2 C and 3 C that are 3 m  apart?

Jul 1, 2018

$F = 6 \times {10}^{9}$

#### Explanation:

Coulomb's law

$F = \frac{k \left({Q}_{1} \cdot {Q}_{2}\right)}{r} ^ 2$

Since the two charges are different (one positive and one negative)
the force will be attraction

Substitute

${Q}_{1} = 2 , \text{ "Q_2=3," } r = 3$

$F = 9 \times {10}^{9} \cdot \left(\frac{2 \times 3}{9}\right)$

$F = 6 \times {10}^{9}$