The number of common integers for two arithmetic progressions 1,8,15,22,...2003 and 2,13,24,35,...2004 is?
I present here a trial solution.
By trial we get
the corresponding values of
So inserting values of
obviously we get the same series by inserting the values of
Hence common terms of both the series constitute an AP.
having first term
Let the last common integer of the series be the
Hence the number of common integers of two given serier is