# Please can anyone help? We're doing simultaneous equations ad I'm a bit confused on how to get the second equation, I got 4s - 14 = 3s.

Jun 3, 2018

Let "C" be the original number of Sweets Charlie has and A be the original number of sweets that Anna has:

Charlie has 4 times as many sweets as Anna thus:
Equation 1: $C = 4 \cdot A$

Charlie eats 14 sweets, Anna eats 2 sweets
$C \to C - 14$ and $A \to A - 2$

and after the change, Charlie has 3 times as many sweets as Anna thus:
Equation 2: $C - 14 = 3 \cdot \left(A - 2\right) = 3 A - 6$

$E q .1 - E q .2 = C - \left(C - 14\right) = 4 A - \left(3 A - 6\right)$
$14 = A + 6$

$A = 8 , A - 2 = 6$
$C = 3 \cdot 6 = 18$

Thus, Charlie now has 18 sweets and Anna now has 6 sweets.