How do you use the chain rule to differentiate #y=(5x^5-4x^3)^-3#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Yahia M. Apr 30, 2018 #dy/dx=(-30x+36x^2)/(5x^2-4x^3)^4# Explanation: #y=(5x^2-4x^3)^-3# Differentiate #dy/dx=-3(5x^2-4x^3)^-4* color(green)(d/dx(5x^2-4x^3)color(blue)(rarr "Chain Rule")# Chain Rule #dy/dx=-3(5x^2-4x^3)^-4*(10x-12x^2)# Simplify #dy/dx=(-30x+36x^2)/(5x^2-4x^3)^4# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1483 views around the world You can reuse this answer Creative Commons License