# How do you solve (3\times 3- ( 2+ 1) ) \div ( 5- 2)?

Mar 3, 2018

$2$, using BODMAS / PEMDAS

#### Explanation:

BODMAS or PEMDAS rule states the order you have to complete operations in:

$B$rackets
$O$f (powers/exponents)
$D$ivision and $M$ultiplication
$A$ddition and $S$ubtraction

Usually we start with the parentheses within the parentheses. In other words, the smallest brackets.

$\left(3 \cdot 3 - \left(2 + 1\right)\right) \div \left(5 - 2\right)$

Here, $\left(2 + 1\right)$ is the most important parenthesis, and should be solved first:

$\left(3 \cdot 3 - 3\right) \div \left(5 - 2\right)$

Now, we have two brackets. What do we do?

Remember, multiplication comes before addition or subtraction, so we complete that operation first $\left(3 \cdot 3\right)$

$\to \left(9 - 3\right) \div \left(5 - 2\right)$

[note: we do not do division now, as it is an operation outside the parentheses]

Now, we have two subtraction operations. Since both are withing brackets, and both are subtraction, they are on the same level on the BODMAS scale. We do them simultaneously:

$\to \left(6\right) \div \left(3\right)$

We can remove the brackets, as there are no more operations within them:

$\to 6 \div 3$

Solve it:

$= 2$

Thus, solved.