# How do you simplify (2x ^ { 3} y ) ^ { 5} \cdot x ^ { 3}?

Jan 31, 2018

$32 \cdot {x}^{18} \cdot {y}^{5}$

#### Explanation:

$\left({\left(2 {x}^{3} y\right)}^{5}\right) \cdot {x}^{3}$

= $\left({2}^{5}\right) \cdot {x}^{3 \cdot 5} \cdot {y}^{5} \cdot {x}^{3}$

= $32 \cdot {x}^{15} \cdot {y}^{5} \cdot {x}^{3}$

= $32 \cdot {x}^{15 + 3} \cdot {y}^{5}$

= $32 \cdot {x}^{18} \cdot {y}^{5}$