# How do you find the slope of the line tangent to the graph of #y = x ln x# at the point ( 1,0 )?

##### 1 Answer

Nov 14, 2016

#### Explanation:

The slope of the tangent at any particular point is given by the derivative.

We have

Differentiating wrt

# dy/dx=(x)(d/dxlnx) + (d/dxx)(lnx) #

# :. dy/dx=(x)(1/x) + (1)(lnx) #

# :. dy/dx=1 + lnx #

So, At

So the required tangent passes through

Using