# How do you find the equation of the tangent line to the curve #y=1+x^3# that is parallel to the line #12x-y=1#?

##### 1 Answer

Oct 25, 2016

#### Explanation:

If the tangent is parallel to

Rearranging the eq of the line to gradient-intercept form,

The first derivative of the curve would be the gradient of the curve, as well as the gradient of tangents to the curve at different points all along the curve.

At the point on the curve where the gradient of the tangent

When

When

Using the point-gradient formula,