How do you find the derivative of #2e^-x#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Henry W. Oct 31, 2016 #(dy)/(dx)=-2e^-x# Explanation: Recall that #d/dxe^x=e^x# Using chain rule, #(dy)/(dx)=(dy)/(du)*(du)/(dx)#, Let #u=-x# #(dy)/(du)=d/(du)2e^u=2e^u=2e^-x# #(du)/(dx)=d/(dx)-x=-1# #:.(dy)/(dx)=-1*2e^-x=-2e^-x# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 9509 views around the world You can reuse this answer Creative Commons License