How do you find the derivative of # 2/(5x+1)^2#? Calculus Basic Differentiation Rules Quotient Rule 1 Answer Henry W. Oct 22, 2016 #(dy)/(dx)=-20/(5x+1)^3# Explanation: #y=2/(5x+1)^2=2(5x+1)^-2# Let #u=5x+1#, #d/(du)2u^-2=-4u^-3=-4(5x+1)^-3# #d/(dx)5x+1=5# Using chain rule, #(dy)/(dx)=(dy)/(du)*(du)/(dx)#, #(dy)/(dx)=-4(5x+1)^-3*5# #=-20(5x+1)^-3# #=-20/(5x+1)^3# Answer link Related questions What is the Quotient Rule for derivatives? How do I use the quotient rule to find the derivative? How do you prove the quotient rule? How do you use the quotient rule to differentiate #y=(2x^4-3x)/(4x-1)#? How do you use the quotient rule to differentiate #y=cos(x)/ln(x)#? How do you use the quotient rule to find the derivative of #y=tan(x)# ? How do you use the quotient rule to find the derivative of #y=x/(x^2+1)# ? How do you use the quotient rule to find the derivative of #y=(e^x+1)/(e^x-1)# ? How do you use the quotient rule to find the derivative of #y=(x-sqrt(x))/(x^(1/3))# ? How do you use the quotient rule to find the derivative of #y=x/(3+e^x)# ? See all questions in Quotient Rule Impact of this question 3662 views around the world You can reuse this answer Creative Commons License