# How do you find #(dy)/(dx)# given #x^2+y^2=1#?

##### 1 Answer

#### Explanation:

Differentiate wrt

We already know how to deal with the first and third terms, so lets get them out the way:

For the remaining term we use the chain rule, we don't know how to differentiate

We can know perform that final differentiation, as we are now differentiating a function of

We can then rearrange to get