How do you evaluate #x^2+2x-1# when #x=2#? Algebra Expressions, Equations, and Functions Expressions with One or More Variables 1 Answer Tanish J. Oct 27, 2014 All you need to do is replace #x# with #2# since it has been given #x=2#. So, #x^2-2x-1 = (2)^2+2(2)-1 = 4+4-1 = 7# Answer link Related questions What is an example of an expression with one or more variables? How do you write expressions with one or more variables? How do you evaluate expressions when you have more than one variables? How do you evaluate the expression #3a+2b# for #a=1# and #b=-2#? How do you find the area of a triangle whose base is 2 inches and height is 4.5 inches? How do you find the volume of a sphere whose radius is 2? How do you evaluate the expression #2(x-y)# for #x=1# and #y=-2#? What is the value of #(3x+8y)/(x-2y)# if #x/(2y)=2#? How do you simplify #6-4t-4#? How do you simplify #2a + b - 3b#? See all questions in Expressions with One or More Variables Impact of this question 7262 views around the world You can reuse this answer Creative Commons License