How do you differentiate #y= ln(1-x^2)^(1/2)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Yahia M. May 3, 2018 #dy/dx=(-x)/(1-x^2)# Explanation: #color(green)(lna^b=blna)# #y=ln(1-x^2)^(1/2)=1/2ln(1-x^2)# #color(green)(d/dxlnu=1/u*color(blue)((du)/dx##rarrcolor(red)("Chain Rule")# Differentiate, #dy/dx=1/2*(1/(1-x^2))*color(blue)((0-2x)# Simplify, #dy/dx=(-x)/(1-x^2)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 7234 views around the world You can reuse this answer Creative Commons License