How do you differentiate #f(x)=(3x^3-2x^2+5)^331#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Henry W. Oct 11, 2016 #(dy)/(dx)=331(9x^2-4x)(3x^3-2x^2+5)^330# Explanation: Using chain rule: #(dy)/(dx)=(dy)/(du)*(du)/(dx)# In this case, #y=(3x^3-2x^2+5)^331# Let #u=3x^3-2x^2+5#, then #(dy)/(du)=331u^330# and #(du)/(dx)=9x^2-4x# So #(dy)/(dx)=331u^330*(9x^2-4x)# #=331(9x^2-4x)(3x^3-2x^2+5)^330# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1906 views around the world You can reuse this answer Creative Commons License