Given that there exists a triangle whose sides are a,b,c. Then prove that there exists a triangle whose #sqrta,sqrtb,sqrtc#?
2 Answers
Given that there exists a triangle whose sides are a,b,c.
So we have following 3 inequalities satisfied.

#a+b>c# 
#b+c>a# 
#c+a>b#
Considering the first one
Similarly from 2nd inequality we get
And from 3rd inequality we get
So we can say if there exists a triangle having sides
My interest in the problem:
Explanation:
Choosing
only, four conjoined
with sides
The graph shows one pair over the base
with vertices.
There are three such pairs, and all have the central
common
graph{(x^2+y^23)((xsqrt2)^2+y^24)(x^2+y^20.01)((xsqrt2)^2+y^20.01)((xsqrt(1/8))^2+(ysqrt((23)/8))^20.01)((xsqrt(1/8))^2+(y+sqrt((23)/8))^20.01)=0[4 4 2 2]}