Find the length of a rectangle lot with a perimeter of 82 meters if the length is 7 meters more then the width?
If the short side of the rectangle = s, then the long side would be s+7.
The total perimeter then would be the sum of all 4 sides, where the sids are equal in pairs, i.e.
Perimeter = s+(s+7)+s+(s+7) = 4s+14 = 82
Therefore 4s=82-14 = 68
As this is the short side, the long side is s+7=17+7=24
The length of the rectangle, therefore, is 24 meters
The length of the rectangle lot is
To start, I'll set up an equation to help solve this...
And combine like terms to get:
Finally divide both sides by
I'll check my work by plugging this info back in to the original equation to see if it works:
The equation works, meaning the length is