# C) A boat is in dry dock and water is allowed in until it floats. The volume of water allowed in is metered and found to be 3450 m3. The dry dock is a rectangular shape 80m long and 20 m wide. ............rest of the question in the picture? plz help

Jul 8, 2018

The length of rectangular dock is $80 m$ and it's width is $20 m$. The volume of water in the dock is $3450 {m}^{3}$

Height of water in the dock with floating boat is $5 m$

So

$\text{volume of displaced water} + 3450 = 80 \times 20 \times 5 {m}^{3}$

$\implies \text{volume of displaced water} = 8000 - 3450 = 4550 {m}^{3}$

Hence the mass of displaced water will be

$4550 {m}^{3} \times 1026 k g \cdot {m}^{-} 3$

$= 4668300 k g$