# Angelica starts on a walk at 5 kilometres an hour. Three hours later, on the same route, Janelle starts riding her bicycle at 11 kilometres an hour. When will Janelle overtake Angelica?

Angelica starts on a walk at 5 kilometres an hour. In 3hrs she walks $15 k m$. =
on the same route, Janelle starts riding her bicycle at 11 kilometres an hour. If Janelle overtakes Angelica after $t$ hr,then
$11 \times t - 5 \times t = 15$
$\implies 6 t = 15$
$\implies t = \frac{15}{6} = 2.5$ hr