# Question #ab9f8

(Sodium) $N a$ atom is more likely to give electron in Gaseous state because its first Ionization energy is less than (Lithium) $L i$ .
This is because the size of $N a$ $\left(g\right)$ atom is bigger than the (Lithium) $L i$ $\left(g\right)$ atom due to the presence of one more Shell.
Thus the outermost ${e}^{-}$of $N a$ $\left(g\right)$atom is far away from nucleus than the outermost ${e}^{-}$in $L i$ $\left(g\right)$ atom, so it is more easy for the ${e}^{-}$ to be released from $N a$ $\left(g\right)$atom.