# Question 20de6

Jan 5, 2018

Tin (IV) Oxide or Stannic Oxide

#### Explanation:

SnO_2 ^#

Oxygen has an oxidation number of -2.
In this equation, the total charge on oxygen would be -4 because there are two of them.
The tin would have to have a +4 charge to balance the charges to a sum of zero.

The stock name is Tin (IV) Oxide.

The old name is Stannic Oxide.
The latin root for tin is stann-
The -ic ending is for the higher oxidation number, $S {n}^{+ 4}$.

If it were the lower oxidation number on tin, $S {n}^{+ 2}$. Then it would end in the -ous ending.