# What mass of water can be produced when "43.2 g" of oxygen gas reacts with an excess of hydrogen gas in the reaction "2H"_2("g") + "O"_2("g")"rarr"2H"_2"O"?

Dec 15, 2017

$\text{48.6 g}$ of Water would be produced from $\text{43.2 g}$ of Oxygen.

#### Explanation:

$\text{O"_2 + "2H"_2}$$\rightarrow$$\text{2H"_2"O}$
43.2cancel("g O"_2) xx ((1cancel("molO"_2))/(32cancel("g O"_2)))xx((2cancel("molH"_2"O"))/(1cancel("molO"_2)))xx((18"g H"_2"O")/(1cancel("mol H"_2"O")))="48.6 g H"_2"O"