# Question #85239

##### 1 Answer

Pretty Huuugeee!

An edited version was added below which yielded an answer of

#### Explanation:

The question provided a value of specific heat capacity with incorrect units. In the answer immediately below, Gaya3 made an assumption that a value of

I, Steve J, am making a different interpretation of what was intended for C. I have added **Answer 2** , below Gaya3's work (and using that format for the math), a solution using

**Answer 1**

Here,

•

#q= 2MJ =2times10^6J#

•#m=10kg#

•#C=3.5 "J""kg"^-1"K"^-1#

•#∆T=?#

So,

**Answer 2**

Here,

•

#q= 2MJ =2times10^6J#

•#m=10kg#

•#C=3.5 " kJ""kg"^-1"K"^-1 = 3.5 times10^3"J""kg"^-1"K"^-1#

•#∆T=?#

So,